HCF

#include<iostream.h>

#include<conio.h>

int n1, n2, a, hcf;

void main()

{

  cout<<"Enter two numbers : ";

  cin>>n1>>n2;

  if(n1<n2)

    a=n1;

  else

    a=n2;

  for(int i=a; i>=1 ; i--)

  {

    if(n1%i==0 && n2%i==0)

    {

      hcf=i;

      break;

    }

  }

  cout<<"\nHCF = "<<hcf;

  getch();

}

.................................................................

OUTPUT :(click to enlarge the image)

LCM

#include<iostream.h>

#include<conio.h>

int n1, n2, lcm,a;

void main()

{

  cout<<"Enter two integers : ";

  cin>>n1>>n2;

  cout<<"\nLCM = ";

  if(n1>n2)

    a=n2;

  else

    a=n1;

  for(int i=a; i<=((n1)*(n2)); i++)

  {

    if(i%n1==0 && i%n2==0)

    {

      lcm=i;

      break;

    }

  }

  cout<<"\n"<<lcm;

  getch();

}

.................................................................

OUTPUT :(click to enlarge the image)

INVERTED TRIANGLE OF (*)

#include<iostream.h>

#include<conio.h>

void main()

{

 clrscr();

 int n;

 cout<<"enter the number of lines :";

 cin>>n;

 for(int i=n; i>=1 ; i--)

 {

   for(int j=i ; j>=1 ; j--)

     cout<<"*";

   cout<<"\n";

 }

 getch();

}

.................................................................

OUTPUT :(click to enlarge the image)

LATERALLY INVERTED TRIANGLE OF ALPHABETS

#include<iostream.h>

#include<conio.h>

void main()

{

 int n;

 cout<<"enter the number of lines :";

 cin>>n;

 for(int i=1 ; i<=n ; i++)

 {

   for(int j=1 ; j<=n-i ; j++)

     cout<<" ";

   for(int k=1 ; k<=i ; k++)

     cout<<char(64+k);

   cout<<"\n";

 }

 getch();

}

.................................................................

OUTPUT :(click to enlarge the image)

LATERALLY INVERTED TRIANGLE OF ALPHABETS

#include<iostream.h>

#include<conio.h>

void main()

{

 int n;

 cout<<"enter the number of lines :";

 cin>>n;

 for(int i=1 ; i<=n ; i++)

 {

   for(int j=1 ; j<=n-i ; j++)

     cout<<" ";

   for(int k=1 ; k<=i ; k++)

     cout<<char(64+k);

   cout<<"\n";

 }

 getch();

}

.................................................................

OUTPUT :(click to enlarge the image)

TRIANGLE OF NUMBERS

#include<iostream.h>

#include<conio.h>

void main()

{

 clrscr();

 int n;

 cout<<"enter the number of lines :";

 cin>>n;

 for(int i=1 ; i<=n ; i++)

 {

   for(int j=1; j<=i ; j++)

     cout<<(0+j);

   cout<<"\n";

 }

 getch();

}

.................................................................

OUTPUT :(click to enlarge the image)

DIAMOND OF (*)

#include<iostream.h>

#include<conio.h>

void main()

{

 clrscr();

 int n, a, b;

 cout<<"enter the number of lines : ";

 cin>>n;

 a=((n/2)+1);

 b=n-a;

 for(int i=1 ; i<=a ; i++)

 {

   for(int j=1 ; j<=a-i ; j++)

     cout<<" ";

   for(int k=1 ; k<=i ; k++)

     cout<<"*";

   for(int l=2 ; l<=i ; l++)

     cout<<"*";

   cout<<"\n";

 }

 int c=b+1;

// int d=b-1;

 for(int p=1; p<=b ; p++)

 {

  for(int q=1 ; q<=p ; q++)

    cout<<" ";

  for(int s=1 ; s<=c-p ; s++)

    cout<<"*";

  for(int r=1 ; r<=b-p ; r++)

    cout<<"*";

  cout<<"\n";

 }

 getch();

}

.................................................................

OUTPUT :(click to enlarge the image)

TRIANGLE OF ALPHABETS

#include<iostream.h>

#include<conio.h>

void main()

{

 clrscr();

 int n;

 cout<<"enter the number of lines :";

 cin>>n;

 for(int i=1 ; i<=n ; i++)

 {

   for(int j=1; j<=i ; j++)

     cout<<char(64+j);

   cout<<"\n";

 }

 getch();

}

.................................................................

OUTPUT :(click to enlarge the image)

CHECKING A LIST OF INTEGERS FOR PALINDROME

#include<iostream.h>

#include<conio.h>

long int rev=0, a[10];

int nmbr;

void revrse(int n)

{

  do

  {

    int temp=n%10;

    rev=(rev*10)+temp;

    n=n/10;

  }while(n!=0);

}

void cmpare(int n)

{

  cout<<"\n\t"<<rev;

  if(n==rev)

    cout<<"PALINDROME";

  else

    cout<<"NON-PALINDROME";

  cout<<"\n";

}

void main()

{

  clrscr();

  cout<<"enter the number of integers : ";

  cin>>nmbr;

  cout<<"Enter the integers : ";

  for(int i=0 ; i<nmbr ; i++)

    cin>>a[i];

  for( i=0 ; i<nmbr ; i++)

  {

    revrse(a[i]);

    cmpare(a[i]);

    rev=0;

  }

  getch();

}

.................................................................
OUTPUT :(click to enlarge the image)

SUM OF DIAGONAL ELEMENTS OF A SQUARE MATRIX

#include<iostream.h>

#include<conio.h>

int x[10][10], n, i, j, b=0 ;

void inpt(int a[10][10] , int n)

{

  for(i=0 ; i<n ; i++)

    for(j=0 ; j<n ; j++)

      cin>>a[i][j];

  cout<<"the matrix :\n";

  for(i=0 ; i<n ; i++)

  {

    cout<<"\n";

    for(j=0 ; j<n ; j++)

      cout<<a[i][j]<<" ";

  }

  cout<<"\n";

}

void otpt(int a[10][10] , int n)

{

  for(i=0 ; i<n/2 ; i++)

  {

    for(j=0 ; j<n ; j++)

    {

      if(j==i || j==n-1-i)

      b=b+a[i][j];

      else

      continue;

    }

  }

  for(i=n-1 ; i>=(n/2) ; i--)

  {

    for(j=0 ; j<n ; j++)

    {

      if(j==i || j==n-1-i)

      b=b+a[i][j];

      else

      continue;

    }

  }

  cout<<"\nSum of diagonal elements = "<<b;

}

void main()

{

  clrscr();

  cout<<"enter the number of rows or columns : ";

  cin>>n;

  cout<<"enter a matrix : ";

  inpt(x,n);

  otpt(x,n);

  getch();

}

.................................................................

OUTPUT :(click to enlarge the image)

DIAGONAL ELEMENTS IN A SQUARE MATRIX

#include<iostream.h>

#include<conio.h>

int x[10][10], n, i, j;

void inpt(int a[10][10] , int n)

{

  for(i=0 ; i<n ; i++)

    for(j=0 ; j<n ; j++)

      cin>>a[i][j];

  cout<<"The matrix :\n";

  for(i=0 ; i<n ; i++)

  {

    cout<<"\n";

    for(j=0 ; j<n ; j++)

      cout<<a[i][j]<<"  ";

  }

  cout<<"\n";

}

void otpt(int a[10][10] , int n)

{

  for(i=0 ; i<n/2 ; i++)

  {

    for(j=0 ; j<n ; j++)

    {

      if(j==i || j==n-1-i)

      cout<<a[i][j]<<" , ";

    }

  }

  for(i=n-1 ; i>=(n/2) ; i--)

  {

    for(j=0 ; j<n ; j++)

    {

      if(j==i || j==n-1-i)

      {

      cout<<a[i][j];

      if(i==n/2)

        cout<<" .";

      else

        cout<<" , ";

      }

    }

  }

}

void main()

{

  clrscr();

  cout<<"Enter the number of rows or columns : ";

  cin>>n;

  cout<<"Enter a matrix : ";

  inpt(x,n);

  cout<<"Diagonal elements : ";

  otpt(x,n);

  getch();

}

.................................................................

OUTPUT :(click to enlarge the image)

COMPARING 2 STRINGS FOR EQUALITY

#include<iostream.h>

#include<conio.h>

#include<string.h>

#include<process.h>

#include<stdio.h>

int len1, len2;

void equal(char a[50], char b[50])

{

  if(len1==len2)

  {

    for(int i=0 ; i<len1 ; i++)

    {

      if(a[i]==b[i])

      continue;

      else

      {

      cout<<"NOT EQUAL";

      getch();

      exit(0);

      }

    }

    cout<<"EQUAL";

  }

  else

    cout<<"NOT EQUAL";

}

void main()

{

  char strng1[25], strng2[25];

  cout<<"enter a string : ";

  gets(strng1);

  len1=strlen(strng1);

  cout<<"enter another string : ";

  gets(strng2);

  len2=strlen(strng2);

  equal(strng1, strng2);

  getch();

}

.................................................................

OUTPUT :(click to enlarge the image)

REVERSING A STRING-WITHOUT USING ANOTHER STRING

#include<iostream.h>

#include<conio.h>

#include<string.h>

#include<stdio.h>

void main()

{

  char strng[25];

  int len;

  cout<<"enter a string : ";

  gets(strng);

  len=strlen(strng);

  cout<<"\n\nreverse : \n";

  for(int i=len-1; i>=0 ; i--)

    cout<<strng[i];

  getch();

}

.................................................................

OUTPUT :(click to enlarge the image)

SEARCH LETTER IN A PARAGRAPH

#include<iostream.h>

#include<conio.h>

#include<string.h>

#include<process.h>

#include<stdio.h>

void main()

{

  char strng1[100], x;

  int len1, len2;

  cout<<"enter a string : ";

  gets(strng1);

  len1=strlen(strng1);

  cout<<"enter the letter to be searched : ";

  cin>>x;

  {

    textcolor(2);

    textbackground(0);

  }

  for(int i=0 ; i<len1 ; i++)

    {

      if(strng1[i]==x)

      {

      cprintf("(");

      cout<<strng1[i];

      cprintf(")");

      }

      else

      cout<<strng1[i];

    }

  getch();

}

.................................................................

OUTPUT :(click to enlarge the image)

REVERSING A STRING-USING ANOTHER STRING

#include<iostream.h>

#include<conio.h>

#include<string.h>

#include<stdio.h>

void main()

{

  char strng[25], rev[25];

  int len;

  cout<<"enter a string : ";

  gets(strng);

  len=strlen(strng);

  for(int i=0 ; i<len ; i++)

  {

    rev[i]=strng[len-1-i];

  }

  cout<<"\n\n reverse :\n";

  puts(rev);

  getch();

}

.................................................................

OUTPUT :(click to enlarge the image)

SUM OF A RANGE

#include<iostream.h>

#include<conio.h>

void main()

{

 int n, m, a=0, b=0;

 cout<<"Enter the starting number :";

 cin>>n;

 cout<<"Enter the last number :";

 cin>>m;

 a=n;

 int i=0;

 do

 {

  a=n+i;

  b=b+a;

  i++;

 }while(i<=m-n);

 cout<<"Sum of the range ="<<b;

 getch();

}

.................................................................

OUTPUT: (click to enlarge the image)

CASE CONVERSION IN A STRING - USING LOGIC

#include<iostream.h>

#include<conio.h>

#include<string.h>

char strng[50];

int len, n;

void cmpltcnvrsion(char strng[50])

{

  for(int i=0 ; i<len ; i++)

  {

    if((97<=int(strng[i]))&&(int(strng[i])<=122))

      cout<<char(int(strng[i])-32);

    else if((65<=int(strng[i]))&&(int(strng[i])<=90))

      cout<<char(int(strng[i])+32);

    else

      cout<<strng[i];

  }

}

void capital(char strng[50])

{

  for(int i=0 ; i<len ; i++)

  {

    if((97<=int(strng[i]))&&(int(strng[i])<=122))

      cout<<char(int(strng[i])-32);

    else

      cout<<strng[i];

  }

}

void small(char strng[50])

{

  for(int i=0 ; i<len ; i++)

  {

    if((65<=int(strng[i]))&&(int(strng[i])<=90))

      cout<<char(int(strng[i])+32);

    else

      cout<<strng[i];

  }

}

void main()

{

  clrscr();

  cout<<"Enter a string :\n";

  cin.getline(strng,50);

  len=strlen(strng);

  cout<<"\n\nChoose the type of conversion : \n 1>Complete conversion \n 2>ALL CAPITAL \n 3>all small \nEnter your choice : ";

  cin>>n;

  switch(n)

  {

    case 1  : cmpltcnvrsion(strng);

    break;

    case 2  : capital(strng);

    break;

    case 3  : small(strng);

    break;

  }

  getch();

}

.................................................................

OUTPUT: (click to enlarge the image)