HCF

#include<iostream.h>

#include<conio.h>

int n1, n2, a, hcf;

void main()

{

  cout<<"Enter two numbers : ";

  cin>>n1>>n2;

  if(n1<n2)

    a=n1;

  else

    a=n2;

  for(int i=a; i>=1 ; i--)

  {

    if(n1%i==0 && n2%i==0)

    {

      hcf=i;

      break;

    }

  }

  cout<<"\nHCF = "<<hcf;

  getch();

}

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OUTPUT :(click to enlarge the image)

LCM

#include<iostream.h>

#include<conio.h>

int n1, n2, lcm,a;

void main()

{

  cout<<"Enter two integers : ";

  cin>>n1>>n2;

  cout<<"\nLCM = ";

  if(n1>n2)

    a=n2;

  else

    a=n1;

  for(int i=a; i<=((n1)*(n2)); i++)

  {

    if(i%n1==0 && i%n2==0)

    {

      lcm=i;

      break;

    }

  }

  cout<<"\n"<<lcm;

  getch();

}

.................................................................

OUTPUT :(click to enlarge the image)

INVERTED TRIANGLE OF (*)

#include<iostream.h>

#include<conio.h>

void main()

{

 clrscr();

 int n;

 cout<<"enter the number of lines :";

 cin>>n;

 for(int i=n; i>=1 ; i--)

 {

   for(int j=i ; j>=1 ; j--)

     cout<<"*";

   cout<<"\n";

 }

 getch();

}

.................................................................

OUTPUT :(click to enlarge the image)

LATERALLY INVERTED TRIANGLE OF ALPHABETS

#include<iostream.h>

#include<conio.h>

void main()

{

 int n;

 cout<<"enter the number of lines :";

 cin>>n;

 for(int i=1 ; i<=n ; i++)

 {

   for(int j=1 ; j<=n-i ; j++)

     cout<<" ";

   for(int k=1 ; k<=i ; k++)

     cout<<char(64+k);

   cout<<"\n";

 }

 getch();

}

.................................................................

OUTPUT :(click to enlarge the image)

LATERALLY INVERTED TRIANGLE OF ALPHABETS

#include<iostream.h>

#include<conio.h>

void main()

{

 int n;

 cout<<"enter the number of lines :";

 cin>>n;

 for(int i=1 ; i<=n ; i++)

 {

   for(int j=1 ; j<=n-i ; j++)

     cout<<" ";

   for(int k=1 ; k<=i ; k++)

     cout<<char(64+k);

   cout<<"\n";

 }

 getch();

}

.................................................................

OUTPUT :(click to enlarge the image)

TRIANGLE OF NUMBERS

#include<iostream.h>

#include<conio.h>

void main()

{

 clrscr();

 int n;

 cout<<"enter the number of lines :";

 cin>>n;

 for(int i=1 ; i<=n ; i++)

 {

   for(int j=1; j<=i ; j++)

     cout<<(0+j);

   cout<<"\n";

 }

 getch();

}

.................................................................

OUTPUT :(click to enlarge the image)

DIAMOND OF (*)

#include<iostream.h>

#include<conio.h>

void main()

{

 clrscr();

 int n, a, b;

 cout<<"enter the number of lines : ";

 cin>>n;

 a=((n/2)+1);

 b=n-a;

 for(int i=1 ; i<=a ; i++)

 {

   for(int j=1 ; j<=a-i ; j++)

     cout<<" ";

   for(int k=1 ; k<=i ; k++)

     cout<<"*";

   for(int l=2 ; l<=i ; l++)

     cout<<"*";

   cout<<"\n";

 }

 int c=b+1;

// int d=b-1;

 for(int p=1; p<=b ; p++)

 {

  for(int q=1 ; q<=p ; q++)

    cout<<" ";

  for(int s=1 ; s<=c-p ; s++)

    cout<<"*";

  for(int r=1 ; r<=b-p ; r++)

    cout<<"*";

  cout<<"\n";

 }

 getch();

}

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OUTPUT :(click to enlarge the image)